English Steve
Senior Bumpkin
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The official answer to the original question is:
S=(BxGa)/A
Where
S = Noseweight;
B = distance from gross centre of gravity to axle centreline (axle always behind CofG)
Ga = load (mass)
A = distance from coupling to centreline of axle
or, transposing the formula to find the centreline of the axle:
B=(SxA)/Ga
So, for any given load
shorter drawbar = higher noseweight
longer drawbar = lower noseweight
For an ordinary general purpose box trailer, you will have to assume that the centre of gravity will be in the middle of the box, as you cannot predict what the trailer will be used to haul. It is then up to the operator to ensure his load is correctly positioned.
Hope this helps everyone.
S=(BxGa)/A
Where
S = Noseweight;
B = distance from gross centre of gravity to axle centreline (axle always behind CofG)
Ga = load (mass)
A = distance from coupling to centreline of axle
or, transposing the formula to find the centreline of the axle:
B=(SxA)/Ga
So, for any given load
shorter drawbar = higher noseweight
longer drawbar = lower noseweight
For an ordinary general purpose box trailer, you will have to assume that the centre of gravity will be in the middle of the box, as you cannot predict what the trailer will be used to haul. It is then up to the operator to ensure his load is correctly positioned.
Hope this helps everyone.