Dr.Al
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Anything will be fine. You'll have 12.8 V across 12.7 kΩ, so from V=I R the current is about 1 mA. Power is I²R so the power in the 2.7 kΩ resistor is about 3 mW (0.003 W).
Anything will be fine. You'll have 12.8 V across 12.7 kΩ, so from V=I R the current is about 1 mA. Power is I²R so the power in the 2.7 kΩ resistor is about 3 mW (0.003 W).
