So I do not clutter up someone else’s thread with my innate questions about why MIG, why Stick etc. I thought best to add this post. Post in question is the one on multipass MIG welding getting towards MMA at the end. vif better on that thread then mods please move and/or edit.
We all try at times to weld metal together a lot thinker then we should be doing and I some times need to understand a bit more of the science to things, just my brain, so here goes.
As per the thread welding two bits of 10mm plate together fillet joint, choice either MIG or MMA.
Am I correct in presuming that with MIG one tries to go for root penetration for strength and in MMA one tries to go for Fillet size?
So why not go for Fillet size with MIG rather then penetration.
As I read it, current density is a factor and for say a constant 125 Amps, the electrode size will effect this. 0.8 MIG wire has a cross section area of 0.502mm2 so will have a current density 249 Amps per square mm.
A 3.2 rod has a csa of 8.8mm2 so would have a current density of 14.2 Amps per square mm
From my reading and trying to understand it all the heat input from a multi-purpose machine would be the same as the formula for ARC Energy is 60VI/1000v
VI is Volts x Amps
v is travel speed in inches or mm (depending on preference)
Heat input is down to efficiency and is 0.8 for MMA/TIG/MIG compared to sub merged arc at 1.
All from TWI web site.
So heat input is the same in both camps.
But trying to understand the figures would suggest that when joining thicker metals together multi-pass MIG could provide more fusion depth and still build up to the same fillet size then MMA with a 3.2mm rod at 125 Amps.
But the general consensus is the other way, why, what have I missed in my thinking?
Probably as clear as mud.
Adrian
We all try at times to weld metal together a lot thinker then we should be doing and I some times need to understand a bit more of the science to things, just my brain, so here goes.
As per the thread welding two bits of 10mm plate together fillet joint, choice either MIG or MMA.
Am I correct in presuming that with MIG one tries to go for root penetration for strength and in MMA one tries to go for Fillet size?
So why not go for Fillet size with MIG rather then penetration.
As I read it, current density is a factor and for say a constant 125 Amps, the electrode size will effect this. 0.8 MIG wire has a cross section area of 0.502mm2 so will have a current density 249 Amps per square mm.
A 3.2 rod has a csa of 8.8mm2 so would have a current density of 14.2 Amps per square mm
From my reading and trying to understand it all the heat input from a multi-purpose machine would be the same as the formula for ARC Energy is 60VI/1000v
VI is Volts x Amps
v is travel speed in inches or mm (depending on preference)
Heat input is down to efficiency and is 0.8 for MMA/TIG/MIG compared to sub merged arc at 1.
All from TWI web site.
So heat input is the same in both camps.
But trying to understand the figures would suggest that when joining thicker metals together multi-pass MIG could provide more fusion depth and still build up to the same fillet size then MMA with a 3.2mm rod at 125 Amps.
But the general consensus is the other way, why, what have I missed in my thinking?
Probably as clear as mud.
Adrian