Olderisbetter
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I am looking for a 12v element about 100w so i was wondering if i put a 1800w 240v kettle on a 12v supply would that be a 90w element or there about?
As above about 4.5w
The element resistance is about 32ohms
1800w/240v= 7.5a
Resistance= v/I
240/7.5=32ohms
I(amps)= v/r
12/32=0.36
Watts = v*I
12x0.36=4.3w
Does that mean the water in the kettle will have evaporated before it boiled
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P=V²/R=144/32=4.5WAs above about 4.5w
The element resistance is about 32ohms
1800w/240v= 7.5a
Resistance= v/I
240/7.5=32ohms
I(amps)= v/r
12/32=0.36
Watts = v*I
12x0.36=4.3w
P=V²/R=144/32=4.5W
Heat loss will mean the water will be colder the longer it’s heatedDoes that mean the water in the kettle will have evaporated before it boiled
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Does that mean the water in the kettle will have evaporated before it boiled
![]()
As above. I’ve a trangia which is a good bit of kit.
What are you doing is the most important question I guess. If it’s for a vehicle and naked flame isn’t an option then either a proper 12v kettle as @8ob or a second battery and a 24v kettle or a 24-240 inverter. You get a lot more grunt with 24v. I’m not an electrician so don’t know the theory but it works fine in lorries for microwave and kettle